Haretown and Tortoiseville are 39 miles apart. A hare travels at 10 miles per hour from Haretown to Tortoiseville, while a tortoise travels at 3 miles per hour from Tortoiseville to Haretown.

If both set out at the same time, how many miles will the hare have to travel before meeting the tortoise en route?


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It can be solved without an equation.
in the first hour - Hare travels 10km & tortoise 3km =13km
in the second hour - Hare travels 10km & tortoise 3km =13km
in the third hour - Hare travels 10km & tortoise 3km =13km
so total=39km

So Hare has to travel 30 km (10 +10 + 10)